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5254341151 = 7032774713
BaseRepresentation
bin1001110010010111…
…01110001000011111
3111120011222012000211
410321023232020133
541230102404101
62225214433251
7244131106603
oct47113561037
914504865024
105254341151
112256a36304
121027802827
13659761207
1437bb8b503
1520b446c51
hex1392ee21f

5254341151 has 4 divisors (see below), whose sum is σ = 5254486192. Its totient is φ = 5254196112.

The previous prime is 5254341143. The next prime is 5254341173. The reversal of 5254341151 is 1511434525.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 5254341151 - 23 = 5254341143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5254321151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32971 + ... + 107683.

It is an arithmetic number, because the mean of its divisors is an integer number (1313621548).

Almost surely, 25254341151 is an apocalyptic number.

5254341151 is a deficient number, since it is larger than the sum of its proper divisors (145041).

5254341151 is an equidigital number, since it uses as much as digits as its factorization.

5254341151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 145040.

The product of its digits is 12000, while the sum is 31.

The square root of 5254341151 is about 72486.8343287248. The cubic root of 5254341151 is about 1738.4922367045.

Adding to 5254341151 its reverse (1511434525), we get a palindrome (6765775676).

The spelling of 5254341151 in words is "five billion, two hundred fifty-four million, three hundred forty-one thousand, one hundred fifty-one".

Divisors: 1 70327 74713 5254341151