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52550004133 = 114777273103
BaseRepresentation
bin110000111100001110…
…010110110110100101
312000122022002210200101
4300330032112312211
51330110300113013
640050252544101
73540144444064
oct607416266645
9160568083611
1052550004133
112031711a990
12a226a82031
134c56159403
14278727a1db
15157869b8dd
hexc3c396da5

52550004133 has 4 divisors (see below), whose sum is σ = 57327277248. Its totient is φ = 47772731020.

The previous prime is 52550004119. The next prime is 52550004139. The reversal of 52550004133 is 33140005525.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 52550004133 - 221 = 52547906981 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (52550004139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2388636541 + ... + 2388636562.

It is an arithmetic number, because the mean of its divisors is an integer number (14331819312).

Almost surely, 252550004133 is an apocalyptic number.

It is an amenable number.

52550004133 is a deficient number, since it is larger than the sum of its proper divisors (4777273115).

52550004133 is a wasteful number, since it uses less digits than its factorization.

52550004133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4777273114.

The product of its (nonzero) digits is 9000, while the sum is 28.

Adding to 52550004133 its reverse (33140005525), we get a palindrome (85690009658).

The spelling of 52550004133 in words is "fifty-two billion, five hundred fifty million, four thousand, one hundred thirty-three".

Divisors: 1 11 4777273103 52550004133