Base | Representation |
---|---|
bin | 10111111001100011111000… |
… | …10010011001001101100111 |
3 | 20220002020102120101110201112 |
4 | 23330301330102121031213 |
5 | 23342031231041434003 |
6 | 303435323540215235 |
7 | 14032665310666532 |
oct | 1374617422311547 |
9 | 226066376343645 |
10 | 52555305030503 |
11 | 15822641637350 |
12 | 5a896a139a51b |
13 | 2342c36c73122 |
14 | cd99943d1a19 |
15 | 61213dc213d8 |
hex | 2fcc7c499367 |
52555305030503 has 4 divisors (see below), whose sum is σ = 57333060033288. Its totient is φ = 47777550027720.
The previous prime is 52555305030491. The next prime is 52555305030541. The reversal of 52555305030503 is 30503050355525.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 52555305030503 - 214 = 52555305014119 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52555305030703) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2388877501376 + ... + 2388877501397.
It is an arithmetic number, because the mean of its divisors is an integer number (14333265008322).
Almost surely, 252555305030503 is an apocalyptic number.
52555305030503 is a deficient number, since it is larger than the sum of its proper divisors (4777755002785).
52555305030503 is a wasteful number, since it uses less digits than its factorization.
52555305030503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4777755002784.
The product of its (nonzero) digits is 843750, while the sum is 41.
The spelling of 52555305030503 in words is "fifty-two trillion, five hundred fifty-five billion, three hundred five million, thirty thousand, five hundred three".
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