Base | Representation |
---|---|
bin | 100110001111010011000… |
… | …1101011001011101001010 |
3 | 200121102110011112120210012 |
4 | 1030132212031121131022 |
5 | 1142101313041024002 |
6 | 15102205254551522 |
7 | 1051462006645154 |
oct | 114364615313512 |
9 | 20542404476705 |
10 | 5255533533002 |
11 | 174694a738a85 |
12 | 70a6836685a2 |
13 | 2c17966a7c2c |
14 | 14252505dad4 |
15 | 91a96230d52 |
hex | 4c7a635974a |
5255533533002 has 4 divisors (see below), whose sum is σ = 7883300299506. Its totient is φ = 2627766766500.
The previous prime is 5255533532971. The next prime is 5255533533023. The reversal of 5255533533002 is 2003353355525.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 5253534459481 + 1999073521 = 2292059^2 + 44711^2 .
It is a super-3 number, since 3×52555335330023 (a number of 39 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1313883383249 + ... + 1313883383252.
Almost surely, 25255533533002 is an apocalyptic number.
5255533533002 is a deficient number, since it is larger than the sum of its proper divisors (2627766766504).
5255533533002 is a wasteful number, since it uses less digits than its factorization.
5255533533002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2627766766503.
The product of its (nonzero) digits is 1012500, while the sum is 41.
Adding to 5255533533002 its reverse (2003353355525), we get a palindrome (7258886888527).
The spelling of 5255533533002 in words is "five trillion, two hundred fifty-five billion, five hundred thirty-three million, five hundred thirty-three thousand, two".
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