Base | Representation |
---|---|
bin | 100110001111101011000… |
… | …1011010010100001010001 |
3 | 200121111112020211022021201 |
4 | 1030133112023102201101 |
5 | 1142104440100133143 |
6 | 15102421203351201 |
7 | 1051520651150605 |
oct | 114372613224121 |
9 | 20544466738251 |
10 | 5256338286673 |
11 | 1747222a26361 |
12 | 70a869082501 |
13 | 2c1894333736 |
14 | 14259dca5505 |
15 | 91ae1be664d |
hex | 4c7d62d2851 |
5256338286673 has 4 divisors (see below), whose sum is σ = 5256737626608. Its totient is φ = 5255938946740.
The previous prime is 5256338286631. The next prime is 5256338286721. The reversal of 5256338286673 is 3766828336525.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5256338286673 - 213 = 5256338278481 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5256338226673) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 199650223 + ... + 199676548.
It is an arithmetic number, because the mean of its divisors is an integer number (1314184406652).
Almost surely, 25256338286673 is an apocalyptic number.
It is an amenable number.
5256338286673 is a deficient number, since it is larger than the sum of its proper divisors (399339935).
5256338286673 is a wasteful number, since it uses less digits than its factorization.
5256338286673 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 399339934.
The product of its digits is 261273600, while the sum is 64.
The spelling of 5256338286673 in words is "five trillion, two hundred fifty-six billion, three hundred thirty-eight million, two hundred eighty-six thousand, six hundred seventy-three".
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