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52577193491 = 318116528511
BaseRepresentation
bin110000111101110110…
…000100111000010011
312000201012021011110122
4300331312010320103
51330134230142431
640053103420455
73540624525254
oct607566047023
9160635234418
1052577193491
1120330500729
12a233bb472b
134c5b988ca4
14278ab16b2b
15157ac6ca7b
hexc3dd84e13

52577193491 has 4 divisors (see below), whose sum is σ = 52593725184. Its totient is φ = 52560661800.

The previous prime is 52577193481. The next prime is 52577193499. The reversal of 52577193491 is 19439177525.

52577193491 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 52577193491 - 234 = 35397324307 is a prime.

It is a super-2 number, since 2×525771934912 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (52577193499) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8261075 + ... + 8267436.

It is an arithmetic number, because the mean of its divisors is an integer number (13148431296).

Almost surely, 252577193491 is an apocalyptic number.

52577193491 is a deficient number, since it is larger than the sum of its proper divisors (16531693).

52577193491 is a wasteful number, since it uses less digits than its factorization.

52577193491 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16531692.

The product of its digits is 2381400, while the sum is 53.

The spelling of 52577193491 in words is "fifty-two billion, five hundred seventy-seven million, one hundred ninety-three thousand, four hundred ninety-one".

Divisors: 1 3181 16528511 52577193491