Base | Representation |
---|---|
bin | 10111111010111110100000… |
… | …10000000010111101000001 |
3 | 20220020220000022011202020201 |
4 | 23331133100100002331001 |
5 | 23343330401313411231 |
6 | 303513531433405201 |
7 | 14036340061214233 |
oct | 1375372020027501 |
9 | 226226008152221 |
10 | 52603958341441 |
11 | 15841239112a31 |
12 | 5a96bbb269801 |
13 | 23476bba0b800 |
14 | cdc08bd2a253 |
15 | 61353a252161 |
hex | 2fd7d0402f41 |
52603958341441 has 24 divisors (see below), whose sum is σ = 60361932164184. Its totient is φ = 45663621120000.
The previous prime is 52603958341427. The next prime is 52603958341511. The reversal of 52603958341441 is 14414385930625.
It can be written as a sum of positive squares in 12 ways, for example, as 31273148217600 + 21330810123841 = 5592240^2 + 4618529^2 .
It is not a de Polignac number, because 52603958341441 - 213 = 52603958333249 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (52603958341241) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4026060 + ... + 11018941.
It is an arithmetic number, because the mean of its divisors is an integer number (2515080506841).
Almost surely, 252603958341441 is an apocalyptic number.
It is an amenable number.
52603958341441 is a deficient number, since it is larger than the sum of its proper divisors (7757973822743).
52603958341441 is a wasteful number, since it uses less digits than its factorization.
52603958341441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15046261 (or 15046248 counting only the distinct ones).
The product of its (nonzero) digits is 12441600, while the sum is 55.
The spelling of 52603958341441 in words is "fifty-two trillion, six hundred three billion, nine hundred fifty-eight million, three hundred forty-one thousand, four hundred forty-one".
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