Base | Representation |
---|---|
bin | 100110010011100011100… |
… | …0101010100111011110011 |
3 | 200122022001020211020002212 |
4 | 1030213013011110323303 |
5 | 1142224023300000201 |
6 | 15110320332202335 |
7 | 1052234361066455 |
oct | 114470705247363 |
9 | 20568036736085 |
10 | 5264675000051 |
11 | 174a810873525 |
12 | 7103b50093ab |
13 | 2c25c255a22c |
14 | 142b5117c2d5 |
15 | 91e2da53abb |
hex | 4c9c7154ef3 |
5264675000051 has 4 divisors (see below), whose sum is σ = 5364008490672. Its totient is φ = 5165341509432.
The previous prime is 5264675000029. The next prime is 5264675000077. The reversal of 5264675000051 is 1500005764625.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5264675000051 - 210 = 5264674999027 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5264674999972 and 5264675000008.
It is not an unprimeable number, because it can be changed into a prime (5264675000021) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49666745231 + ... + 49666745336.
It is an arithmetic number, because the mean of its divisors is an integer number (1341002122668).
Almost surely, 25264675000051 is an apocalyptic number.
5264675000051 is a deficient number, since it is larger than the sum of its proper divisors (99333490621).
5264675000051 is an equidigital number, since it uses as much as digits as its factorization.
5264675000051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 99333490620.
The product of its (nonzero) digits is 252000, while the sum is 41.
The spelling of 5264675000051 in words is "five trillion, two hundred sixty-four billion, six hundred seventy-five million, fifty-one", and thus it is an aban number.
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