Base | Representation |
---|---|
bin | 110001000101010001… |
… | …000101111111110111 |
3 | 12001000212120120212212 |
4 | 301011101011333313 |
5 | 1330413114411341 |
6 | 40113312404035 |
7 | 3543666125105 |
oct | 610521057767 |
9 | 161025516785 |
10 | 52701716471 |
11 | 20394821688 |
12 | a26984661b |
13 | 4c7b707821 |
14 | 279d48cc75 |
15 | 1586b685eb |
hex | c45445ff7 |
52701716471 has 4 divisors (see below), whose sum is σ = 54993095472. Its totient is φ = 50410337472.
The previous prime is 52701716467. The next prime is 52701716489. The reversal of 52701716471 is 17461710725.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 52701716471 - 22 = 52701716467 is a prime.
It is a super-3 number, since 3×527017164713 (a number of 33 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52701716491) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1145689466 + ... + 1145689511.
It is an arithmetic number, because the mean of its divisors is an integer number (13748273868).
Almost surely, 252701716471 is an apocalyptic number.
52701716471 is a deficient number, since it is larger than the sum of its proper divisors (2291379001).
52701716471 is a wasteful number, since it uses less digits than its factorization.
52701716471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2291379000.
The product of its (nonzero) digits is 82320, while the sum is 41.
The spelling of 52701716471 in words is "fifty-two billion, seven hundred one million, seven hundred sixteen thousand, four hundred seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •