Base | Representation |
---|---|
bin | 100110010111001101000… |
… | …0110000001111110111111 |
3 | 200200001021022000210122001 |
4 | 1030232122012001332333 |
5 | 1142341100044110242 |
6 | 15114054022403131 |
7 | 1052632500525160 |
oct | 114563206017677 |
9 | 20601238023561 |
10 | 5272510144447 |
11 | 1753071582477 |
12 | 711a20b904a7 |
13 | 2c327089c750 |
14 | 1432959b1767 |
15 | 9223b837eb7 |
hex | 4cb9a181fbf |
5272510144447 has 16 divisors (see below), whose sum is σ = 6489464647680. Its totient is φ = 4171514054112.
The previous prime is 5272510144397. The next prime is 5272510144463. The reversal of 5272510144447 is 7444410152725.
It is a cyclic number.
It is not a de Polignac number, because 5272510144447 - 211 = 5272510142399 is a prime.
It is a super-3 number, since 3×52725101444473 (a number of 39 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5272510144397 and 5272510144406.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5272510154447) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1734588 + ... + 3681550.
It is an arithmetic number, because the mean of its divisors is an integer number (405591540480).
Almost surely, 25272510144447 is an apocalyptic number.
5272510144447 is a deficient number, since it is larger than the sum of its proper divisors (1216954503233).
5272510144447 is a wasteful number, since it uses less digits than its factorization.
5272510144447 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1976742.
The product of its (nonzero) digits is 1254400, while the sum is 46.
The spelling of 5272510144447 in words is "five trillion, two hundred seventy-two billion, five hundred ten million, one hundred forty-four thousand, four hundred forty-seven".
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