Base | Representation |
---|---|
bin | 110001000111100100… |
… | …100001101101001101 |
3 | 12001010120022010212210 |
4 | 301013210201231031 |
5 | 1331003013141013 |
6 | 40121213021033 |
7 | 3544645464321 |
oct | 610744415515 |
9 | 161116263783 |
10 | 52740365133 |
11 | 20404619a25 |
12 | a27a784779 |
13 | 4c8671a261 |
14 | 27a466d981 |
15 | 158a24ecc3 |
hex | c47921b4d |
52740365133 has 16 divisors (see below), whose sum is σ = 71027496000. Its totient is φ = 34806844800.
The previous prime is 52740365071. The next prime is 52740365159. The reversal of 52740365133 is 33156304725.
It is a de Polignac number, because none of the positive numbers 2k-52740365133 is a prime.
It is a super-2 number, since 2×527403651332 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 52740365091 and 52740365100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52740365933) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3947178 + ... + 3960516.
It is an arithmetic number, because the mean of its divisors is an integer number (4439218500).
Almost surely, 252740365133 is an apocalyptic number.
It is an amenable number.
52740365133 is a deficient number, since it is larger than the sum of its proper divisors (18287130867).
52740365133 is a wasteful number, since it uses less digits than its factorization.
52740365133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26492.
The product of its (nonzero) digits is 226800, while the sum is 39.
Adding to 52740365133 its reverse (33156304725), we get a palindrome (85896669858).
The spelling of 52740365133 in words is "fifty-two billion, seven hundred forty million, three hundred sixty-five thousand, one hundred thirty-three".
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