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52752540373 = 134057887721
BaseRepresentation
bin110001001000010010…
…111110001011010101
312001011102012201011121
4301020102332023111
51331014122242443
640122330003541
73545154123541
oct611022761325
9161142181147
1052752540373
1120410485405
12a2828765b1
134c890c0c40
1427a611ca21
15158b3574ed
hexc484be2d5

52752540373 has 4 divisors (see below), whose sum is σ = 56810428108. Its totient is φ = 48694652640.

The previous prime is 52752540359. The next prime is 52752540377. The reversal of 52752540373 is 37304525725.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2550553009 + 50201987364 = 50503^2 + 224058^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-52752540373 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (52752540377) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2028943848 + ... + 2028943873.

It is an arithmetic number, because the mean of its divisors is an integer number (14202607027).

Almost surely, 252752540373 is an apocalyptic number.

It is an amenable number.

52752540373 is a deficient number, since it is larger than the sum of its proper divisors (4057887735).

52752540373 is a wasteful number, since it uses less digits than its factorization.

52752540373 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4057887734.

The product of its (nonzero) digits is 882000, while the sum is 43.

The spelling of 52752540373 in words is "fifty-two billion, seven hundred fifty-two million, five hundred forty thousand, three hundred seventy-three".

Divisors: 1 13 4057887721 52752540373