Base | Representation |
---|---|
bin | 100110011001100001111… |
… | …0100110110001100000111 |
3 | 200200112011102012110100110 |
4 | 1030303003310312030013 |
5 | 1142431312321000210 |
6 | 15120241421044103 |
7 | 1053200333316243 |
oct | 114630364661407 |
9 | 20615142173313 |
10 | 5277505250055 |
11 | 17551a5147225 |
12 | 7129959b6633 |
13 | 2c388870663c |
14 | 14360b15b423 |
15 | 92430124420 |
hex | 4ccc3d36307 |
5277505250055 has 8 divisors (see below), whose sum is σ = 8444008400112. Its totient is φ = 2814669466688.
The previous prime is 5277505250021. The next prime is 5277505250063. The reversal of 5277505250055 is 5500525057725.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5277505250055 - 215 = 5277505217287 is a prime.
It is a super-3 number, since 3×52775052500553 (a number of 39 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5277505249986 and 5277505250013.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 175916841654 + ... + 175916841683.
It is an arithmetic number, because the mean of its divisors is an integer number (1055501050014).
Almost surely, 25277505250055 is an apocalyptic number.
5277505250055 is a deficient number, since it is larger than the sum of its proper divisors (3166503150057).
5277505250055 is a wasteful number, since it uses less digits than its factorization.
5277505250055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 351833683345.
The product of its (nonzero) digits is 3062500, while the sum is 48.
The spelling of 5277505250055 in words is "five trillion, two hundred seventy-seven billion, five hundred five million, two hundred fifty thousand, fifty-five".
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