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528314113 = 1459362107
BaseRepresentation
bin11111011111010…
…110111100000001
31100211010010201101
4133133112330001
52040222022423
6124231334401
716043411245
oct3737267401
91324103641
10528314113
11251246238
12128b21401
13855b9902
1450246425
15315ac7ad
hex1f7d6f01

528314113 has 4 divisors (see below), whose sum is σ = 528677680. Its totient is φ = 527950548.

The previous prime is 528314077. The next prime is 528314153. The reversal of 528314113 is 311413825.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 528314113 - 221 = 526216961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (528314153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 179595 + ... + 182512.

It is an arithmetic number, because the mean of its divisors is an integer number (132169420).

Almost surely, 2528314113 is an apocalyptic number.

It is an amenable number.

528314113 is a deficient number, since it is larger than the sum of its proper divisors (363567).

528314113 is a wasteful number, since it uses less digits than its factorization.

528314113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 363566.

The product of its digits is 2880, while the sum is 28.

The square root of 528314113 is about 22985.0845767424. The cubic root of 528314113 is about 808.4082508898.

Adding to 528314113 its reverse (311413825), we get a palindrome (839727938).

The spelling of 528314113 in words is "five hundred twenty-eight million, three hundred fourteen thousand, one hundred thirteen".

Divisors: 1 1459 362107 528314113