530000035 has 4 divisors (see below), whose sum is σ = 636000048. Its totient is φ = 424000024.

The previous prime is 530000033. The next prime is 530000039.

It is a happy number.

530000035 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 530000035 - 2¹ = 530000033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 529999973 and 530000018.

It is not an unprimeable number, because it can be changed into a prime (530000033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52999999 + ... + 53000008.

It is an arithmetic number, because the mean of its divisors is an integer number (159000012).

Almost surely, 2^530000035 is an apocalyptic number.

530000035 is a deficient number, since it is larger than the sum of its proper divisors (106000013).

530000035 is a wasteful number, since it uses less digits than its factorization.

530000035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 106000012.

The product of its (nonzero) digits is 225, while the sum is 16.

The square root of 530000035 is about 23021.7296265941. The cubic root of 530000035 is about 809.2672512707.

It can be divided in two parts, 5300000 and 35, that added together give a palindrome (5300035).

The spelling of 530000035 in words is "five hundred thirty million, thirty-five", and thus it is an aban number.