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53000200035 = 3257731523651
BaseRepresentation
bin110001010111000011…
…101101111101100011
312001210200020010100200
4301113003231331203
51332021022400120
640203054120243
73554252160426
oct612703557543
9161720203320
1053000200035
112052825a812
12a3317b0083
134cc84c4313
1427cad899bd
1515a2e77e90
hexc570edf63

53000200035 has 24 divisors (see below), whose sum is σ = 91985918544. Its totient is φ = 28230187200.

The previous prime is 53000200021. The next prime is 53000200039.

53000200035 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 53000200035 - 214 = 53000183651 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53000199990 and 53000200017.

It is not an unprimeable number, because it can be changed into a prime (53000200039) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 727041 + ... + 796610.

It is an arithmetic number, because the mean of its divisors is an integer number (3832746606).

Almost surely, 253000200035 is an apocalyptic number.

53000200035 is a deficient number, since it is larger than the sum of its proper divisors (38985718509).

53000200035 is a wasteful number, since it uses less digits than its factorization.

53000200035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1524435 (or 1524432 counting only the distinct ones).

The product of its (nonzero) digits is 450, while the sum is 18.

The spelling of 53000200035 in words is "fifty-three billion, two hundred thousand, thirty-five".

Divisors: 1 3 5 9 15 45 773 2319 3865 6957 11595 34785 1523651 4570953 7618255 13712859 22854765 68564295 1177782223 3533346669 5888911115 10600040007 17666733345 53000200035