Base | Representation |
---|---|
bin | 11000000110100000101000… |
… | …00101110100100110011111 |
3 | 20221122202212101210201200020 |
4 | 30003100110011310212133 |
5 | 23421323434234100020 |
6 | 304415545433403223 |
7 | 14110066123421322 |
oct | 1403202405644637 |
9 | 227582771721606 |
10 | 53000233503135 |
11 | 15984300110166 |
12 | 5b3b972b69513 |
13 | 2375b9273a7c9 |
14 | d133215247b9 |
15 | 61d9ceb29c40 |
hex | 30341417499f |
53000233503135 has 8 divisors (see below), whose sum is σ = 84800373605040. Its totient is φ = 28266791201664.
The previous prime is 53000233503121. The next prime is 53000233503167. The reversal of 53000233503135 is 53130533200035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 53000233503135 - 211 = 53000233501087 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53000233503096 and 53000233503105.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1766674450090 + ... + 1766674450119.
It is an arithmetic number, because the mean of its divisors is an integer number (10600046700630).
Almost surely, 253000233503135 is an apocalyptic number.
53000233503135 is a deficient number, since it is larger than the sum of its proper divisors (31800140101905).
53000233503135 is a wasteful number, since it uses less digits than its factorization.
53000233503135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3533348900217.
The product of its (nonzero) digits is 60750, while the sum is 33.
The spelling of 53000233503135 in words is "fifty-three trillion, two hundred thirty-three million, five hundred three thousand, one hundred thirty-five".
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