Base | Representation |
---|---|
bin | 111100010000010101100111… |
… | …0011110101010101011001111 |
3 | 2120111121120002011100110021020 |
4 | 1320200223032132222223033 |
5 | 1023432200031203002412 |
6 | 5115123411151405223 |
7 | 216432014060431413 |
oct | 17040531636525317 |
9 | 2514546064313236 |
10 | 530011018406607 |
11 | 143972457593891 |
12 | 4b53b829823813 |
13 | 19997a947a365a |
14 | 94c4954d08d43 |
15 | 4141c09ba018c |
hex | 1e20ace7aaacf |
530011018406607 has 8 divisors (see below), whose sum is σ = 706715558285184. Its totient is φ = 353323578732888.
The previous prime is 530011018406599. The next prime is 530011018406627. The reversal of 530011018406607 is 706604810110035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 530011018406607 - 23 = 530011018406599 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530011018406627) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4274978893 + ... + 4275102870.
It is an arithmetic number, because the mean of its divisors is an integer number (88339444785648).
Almost surely, 2530011018406607 is an apocalyptic number.
530011018406607 is a deficient number, since it is larger than the sum of its proper divisors (176704539878577).
530011018406607 is a wasteful number, since it uses less digits than its factorization.
530011018406607 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8550102429.
The product of its (nonzero) digits is 120960, while the sum is 42.
The spelling of 530011018406607 in words is "five hundred thirty trillion, eleven billion, eighteen million, four hundred six thousand, six hundred seven".
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