Base | Representation |
---|---|
bin | 111100010000011010000011… |
… | …0000110100001001100111111 |
3 | 2120111122110122211210111120200 |
4 | 1320200310012012201030333 |
5 | 1023432324032113110124 |
6 | 5115132024141214543 |
7 | 216432502054615302 |
oct | 17040640606411477 |
9 | 2514573584714520 |
10 | 530020541535039 |
11 | 1439764a40a9165 |
12 | 4b541646b61453 |
13 | 199989517460a9 |
14 | 94c51b99b6b39 |
15 | 41420b5c62bc9 |
hex | 1e20d061a133f |
530020541535039 has 36 divisors (see below), whose sum is σ = 786851660059920. Its totient is φ = 343790243222400.
The previous prime is 530020541535007. The next prime is 530020541535073. The reversal of 530020541535039 is 930535145020035.
530020541535039 is a `hidden beast` number, since 5 + 3 + 0 + 0 + 2 + 0 + 541 + 53 + 50 + 3 + 9 = 666.
It is not a de Polignac number, because 530020541535039 - 25 = 530020541535007 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 530020541534985 and 530020541535003.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530020541535539) by changing a digit.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 657550942 + ... + 658356500.
It is an arithmetic number, because the mean of its divisors is an integer number (21856990557220).
Almost surely, 2530020541535039 is an apocalyptic number.
530020541535039 is a deficient number, since it is larger than the sum of its proper divisors (256831118524881).
530020541535039 is a wasteful number, since it uses less digits than its factorization.
530020541535039 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 859040 (or 859000 counting only the distinct ones).
The product of its (nonzero) digits is 1215000, while the sum is 45.
The spelling of 530020541535039 in words is "five hundred thirty trillion, twenty billion, five hundred forty-one million, five hundred thirty-five thousand, thirty-nine".
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