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530024234345 = 5106004846869
BaseRepresentation
bin1111011011001111110…
…01111111110101101001
31212200002022002211212222
413231213321333311221
532140442200444340
61043253442443425
753202331441304
oct7554771776551
91780068084788
10530024234345
11194866954111
1286880063575
133ac9a549708
141b920979b3b
15dbc19478b5
hex7b67e7fd69

530024234345 has 4 divisors (see below), whose sum is σ = 636029081220. Its totient is φ = 424019387472.

The previous prime is 530024234293. The next prime is 530024234401. The reversal of 530024234345 is 543432420035.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 392142721369 + 137881512976 = 626213^2 + 371324^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-530024234345 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53002423430 + ... + 53002423439.

It is an arithmetic number, because the mean of its divisors is an integer number (159007270305).

Almost surely, 2530024234345 is an apocalyptic number.

It is an amenable number.

530024234345 is a deficient number, since it is larger than the sum of its proper divisors (106004846875).

530024234345 is a wasteful number, since it uses less digits than its factorization.

530024234345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 106004846874.

The product of its (nonzero) digits is 172800, while the sum is 35.

The spelling of 530024234345 in words is "five hundred thirty billion, twenty-four million, two hundred thirty-four thousand, three hundred forty-five".

Divisors: 1 5 106004846869 530024234345