Base | Representation |
---|---|
bin | 1111011011001111110… |
… | …01111111110101101001 |
3 | 1212200002022002211212222 |
4 | 13231213321333311221 |
5 | 32140442200444340 |
6 | 1043253442443425 |
7 | 53202331441304 |
oct | 7554771776551 |
9 | 1780068084788 |
10 | 530024234345 |
11 | 194866954111 |
12 | 86880063575 |
13 | 3ac9a549708 |
14 | 1b920979b3b |
15 | dbc19478b5 |
hex | 7b67e7fd69 |
530024234345 has 4 divisors (see below), whose sum is σ = 636029081220. Its totient is φ = 424019387472.
The previous prime is 530024234293. The next prime is 530024234401. The reversal of 530024234345 is 543432420035.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 392142721369 + 137881512976 = 626213^2 + 371324^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-530024234345 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53002423430 + ... + 53002423439.
It is an arithmetic number, because the mean of its divisors is an integer number (159007270305).
Almost surely, 2530024234345 is an apocalyptic number.
It is an amenable number.
530024234345 is a deficient number, since it is larger than the sum of its proper divisors (106004846875).
530024234345 is a wasteful number, since it uses less digits than its factorization.
530024234345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 106004846874.
The product of its (nonzero) digits is 172800, while the sum is 35.
The spelling of 530024234345 in words is "five hundred thirty billion, twenty-four million, two hundred thirty-four thousand, three hundred forty-five".
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