53003035 has 4 divisors (see below), whose sum is σ = 63603648. Its totient is φ = 42402424.

The previous prime is 53003033. The next prime is 53003051. The reversal of 53003035 is 53030035.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53030035 = 5 ⋅10606007.

It is a cyclic number.

It is not a de Polignac number, because 53003035 - 2¹ = 53003033 is a prime.

It is a super-2 number, since 2×53003035² = 5618643438422450, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53003033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5300299 + ... + 5300308.

It is an arithmetic number, because the mean of its divisors is an integer number (15900912).

Almost surely, 2^53003035 is an apocalyptic number.

53003035 is a deficient number, since it is larger than the sum of its proper divisors (10600613).

53003035 is a wasteful number, since it uses less digits than its factorization.

53003035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10600612.

The product of its (nonzero) digits is 675, while the sum is 19.

The square root of 53003035 is about 7280.3183309523. The cubic root of 53003035 is about 375.6357453024.

Subtracting 53003035 from its reverse (53030035), we obtain a cube (27000 = 30³).

The spelling of 53003035 in words is "fifty-three million, three thousand, thirty-five".