53030035 has 4 divisors (see below), whose sum is σ = 63636048. Its totient is φ = 42424024.

The previous prime is 53030011. The next prime is 53030041. The reversal of 53030035 is 53003035.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53003035 = 5 ⋅10600607.

It is a cyclic number.

It is not a de Polignac number, because 53030035 - 2²³ = 44641427 is a prime.

It is a super-2 number, since 2×53030035² = 5624369224202450, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53029994 and 53030021.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5302999 + ... + 5303008.

It is an arithmetic number, because the mean of its divisors is an integer number (15909012).

Almost surely, 2^53030035 is an apocalyptic number.

53030035 is a deficient number, since it is larger than the sum of its proper divisors (10606013).

53030035 is a wasteful number, since it uses less digits than its factorization.

53030035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10606012.

The product of its (nonzero) digits is 675, while the sum is 19.

The square root of 53030035 is about 7282.1724093844. The cubic root of 53030035 is about 375.6995180244.

Subtracting from 53030035 its reverse (53003035), we obtain a cube (27000 = 30³).

The spelling of 53030035 in words is "fifty-three million, thirty thousand, thirty-five".