Base | Representation |
---|---|
bin | 1111011011010001010… |
… | …01000001010101100101 |
3 | 1212200010011022010020010 |
4 | 13231220221001111211 |
5 | 32141003324430003 |
6 | 1043255003000433 |
7 | 53202541301643 |
oct | 7555051012545 |
9 | 1780104263203 |
10 | 530036561253 |
11 | 194872903541 |
12 | 86884209119 |
13 | 3ac9cc74444 |
14 | 1b922468193 |
15 | dbc2a80003 |
hex | 7b68a41565 |
530036561253 has 8 divisors (see below), whose sum is σ = 706732400448. Its totient is φ = 353349214784.
The previous prime is 530036561227. The next prime is 530036561387. The reversal of 530036561253 is 352165630035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 530036561253 - 29 = 530036560741 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530036561653) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1976100 + ... + 2228237.
It is an arithmetic number, because the mean of its divisors is an integer number (88341550056).
Almost surely, 2530036561253 is an apocalyptic number.
It is an amenable number.
530036561253 is a deficient number, since it is larger than the sum of its proper divisors (176695839195).
530036561253 is a wasteful number, since it uses less digits than its factorization.
530036561253 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4246363.
The product of its (nonzero) digits is 243000, while the sum is 39.
The spelling of 530036561253 in words is "five hundred thirty billion, thirty-six million, five hundred sixty-one thousand, two hundred fifty-three".
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