Base | Representation |
---|---|
bin | 11000000110101000001111… |
… | …10011011111110011000011 |
3 | 20221200011102100200011102221 |
4 | 30003110013303133303003 |
5 | 23421410323004340120 |
6 | 304421503255351511 |
7 | 14110302343104523 |
oct | 1403240763376303 |
9 | 227604370604387 |
10 | 53004322340035 |
11 | 15986009160910 |
12 | 5b40714382597 |
13 | 2376394894921 |
14 | d135cc5a1683 |
15 | 61db6da9c0aa |
hex | 303507cdfcc3 |
53004322340035 has 16 divisors (see below), whose sum is σ = 70035957614592. Its totient is φ = 38188330789600.
The previous prime is 53004322340033. The next prime is 53004322340069.
53004322340035 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 53004322340035 - 21 = 53004322340033 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53004322340033) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4503335011 + ... + 4503346780.
It is an arithmetic number, because the mean of its divisors is an integer number (4377247350912).
Almost surely, 253004322340035 is an apocalyptic number.
53004322340035 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53004322340035 is a deficient number, since it is larger than the sum of its proper divisors (17031635274557).
53004322340035 is a wasteful number, since it uses less digits than its factorization.
53004322340035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9006681914.
The product of its (nonzero) digits is 129600, while the sum is 34.
It can be divided in two parts, 5300432 and 2340035, that added together give a palindrome (7640467).
The spelling of 53004322340035 in words is "fifty-three trillion, four billion, three hundred twenty-two million, three hundred forty thousand, thirty-five".
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