Base | Representation |
---|---|
bin | 110001010111010100… |
… | …001010110001001111 |
3 | 12001210222100012201111 |
4 | 301113110022301033 |
5 | 1332023123343320 |
6 | 40203330352451 |
7 | 3554333630635 |
oct | 612724126117 |
9 | 161728305644 |
10 | 53004512335 |
11 | 2052a7356a5 |
12 | a33312b727 |
13 | 4cc9374088 |
14 | 27cb78d355 |
15 | 15a352aa5a |
hex | c5750ac4f |
53004512335 has 16 divisors (see below), whose sum is σ = 64698393600. Its totient is φ = 41675289376.
The previous prime is 53004512333. The next prime is 53004512339. The reversal of 53004512335 is 53321540035.
53004512335 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 53004512335 - 21 = 53004512333 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53004512297 and 53004512306.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53004512333) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1432842 + ... + 1469368.
It is an arithmetic number, because the mean of its divisors is an integer number (4043649600).
Almost surely, 253004512335 is an apocalyptic number.
53004512335 is a deficient number, since it is larger than the sum of its proper divisors (11693881265).
53004512335 is a wasteful number, since it uses less digits than its factorization.
53004512335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41510.
The product of its (nonzero) digits is 27000, while the sum is 31.
The spelling of 53004512335 in words is "fifty-three billion, four million, five hundred twelve thousand, three hundred thirty-five".
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