Base | Representation |
---|---|
bin | 110001010111101010… |
… | …010010110011101111 |
3 | 12001211101020212221212 |
4 | 301113222102303233 |
5 | 1332031114444211 |
6 | 40204054545035 |
7 | 3554434135556 |
oct | 612752226357 |
9 | 161741225855 |
10 | 53010312431 |
11 | 20532a3736a |
12 | a33506817b |
13 | 4cca62509b |
14 | 27cc45cd9d |
15 | 15a3cc438b |
hex | c57a92cef |
53010312431 has 4 divisors (see below), whose sum is σ = 53801511192. Its totient is φ = 52219113672.
The previous prime is 53010312391. The next prime is 53010312451. The reversal of 53010312431 is 13421301035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53010312431 - 26 = 53010312367 is a prime.
It is a super-2 number, since 2×530103124312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53010312397 and 53010312406.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53010312451) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 395599280 + ... + 395599413.
It is an arithmetic number, because the mean of its divisors is an integer number (13450377798).
Almost surely, 253010312431 is an apocalyptic number.
53010312431 is a deficient number, since it is larger than the sum of its proper divisors (791198761).
53010312431 is an equidigital number, since it uses as much as digits as its factorization.
53010312431 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 791198760.
The product of its (nonzero) digits is 1080, while the sum is 23.
Adding to 53010312431 its reverse (13421301035), we get a palindrome (66431613466).
The spelling of 53010312431 in words is "fifty-three billion, ten million, three hundred twelve thousand, four hundred thirty-one".
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