Base | Representation |
---|---|
bin | 111100010001000000100101… |
… | …1000100110110101011000111 |
3 | 2120111221101021122021212200211 |
4 | 1320202001023010312223013 |
5 | 1023440203031043331343 |
6 | 5115234032345020251 |
7 | 216441462011430031 |
oct | 17042011304665307 |
9 | 2514841248255624 |
10 | 530103303105223 |
11 | 1439a8603924851 |
12 | 4b5556a3784687 |
13 | 199a36b0a411b3 |
14 | 94c91cb410c51 |
15 | 414430b8c979d |
hex | 1e2204b136ac7 |
530103303105223 has 8 divisors (see below), whose sum is σ = 536813908649280. Its totient is φ = 523392708490080.
The previous prime is 530103303105163. The next prime is 530103303105227. The reversal of 530103303105223 is 322501303301035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 530103303105223 - 213 = 530103303097031 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530103303105227) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 145412961 + ... + 149013877.
It is an arithmetic number, because the mean of its divisors is an integer number (67101738581160).
Almost surely, 2530103303105223 is an apocalyptic number.
530103303105223 is a deficient number, since it is larger than the sum of its proper divisors (6710605544057).
530103303105223 is a wasteful number, since it uses less digits than its factorization.
530103303105223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5464457.
The product of its (nonzero) digits is 24300, while the sum is 31.
Adding to 530103303105223 its reverse (322501303301035), we get a palindrome (852604606406258).
The spelling of 530103303105223 in words is "five hundred thirty trillion, one hundred three billion, three hundred three million, one hundred five thousand, two hundred twenty-three".
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