Base | Representation |
---|---|
bin | 111100010001000000100101… |
… | …1000100111000010110100011 |
3 | 2120111221101021122022020010111 |
4 | 1320202001023010320112203 |
5 | 1023440203031044041344 |
6 | 5115234032345112151 |
7 | 216441462011456053 |
oct | 17042011304702643 |
9 | 2514841248266114 |
10 | 530103303112099 |
11 | 1439a8603929a32 |
12 | 4b5556a3788657 |
13 | 199a36b0a44372 |
14 | 94c91cb413563 |
15 | 414430b8cb834 |
hex | 1e2204b1385a3 |
530103303112099 has 4 divisors (see below), whose sum is σ = 544430419412464. Its totient is φ = 515776186811736.
The previous prime is 530103303112073. The next prime is 530103303112109. The reversal of 530103303112099 is 990211303301035.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 530103303112099 - 219 = 530103302587811 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (530103303112049) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7163558150127 + ... + 7163558150200.
It is an arithmetic number, because the mean of its divisors is an integer number (136107604853116).
Almost surely, 2530103303112099 is an apocalyptic number.
530103303112099 is a deficient number, since it is larger than the sum of its proper divisors (14327116300365).
530103303112099 is a wasteful number, since it uses less digits than its factorization.
530103303112099 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14327116300364.
The product of its (nonzero) digits is 65610, while the sum is 40.
The spelling of 530103303112099 in words is "five hundred thirty trillion, one hundred three billion, three hundred three million, one hundred twelve thousand, ninety-nine".
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