Base | Representation |
---|---|
bin | 11111100110001… |
… | …011111000100001 |
3 | 1100221111001202121 |
4 | 133212023320201 |
5 | 2041201310331 |
6 | 124333544241 |
7 | 16064544151 |
oct | 3746137041 |
9 | 1327431677 |
10 | 530103841 |
11 | 252258953 |
12 | 129645081 |
13 | 85a95417 |
14 | 50590761 |
15 | 31812c11 |
hex | 1f98be21 |
530103841 has 4 divisors (see below), whose sum is σ = 532303684. Its totient is φ = 527904000.
The previous prime is 530103823. The next prime is 530103869. The reversal of 530103841 is 148301035.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 148301035 = 5 ⋅29660207.
It can be written as a sum of positive squares in 2 ways, for example, as 464833600 + 65270241 = 21560^2 + 8079^2 .
It is a cyclic number.
It is not a de Polignac number, because 530103841 - 27 = 530103713 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (530103811) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1099560 + ... + 1100041.
It is an arithmetic number, because the mean of its divisors is an integer number (133075921).
Almost surely, 2530103841 is an apocalyptic number.
It is an amenable number.
530103841 is a deficient number, since it is larger than the sum of its proper divisors (2199843).
530103841 is a wasteful number, since it uses less digits than its factorization.
530103841 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2199842.
The product of its (nonzero) digits is 1440, while the sum is 25.
The square root of 530103841 is about 23023.9840383892. The cubic root of 530103841 is about 809.3200822813.
Adding to 530103841 its reverse (148301035), we get a palindrome (678404876).
The spelling of 530103841 in words is "five hundred thirty million, one hundred three thousand, eight hundred forty-one".
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