Base | Representation |
---|---|
bin | 11111100110001… |
… | …101101000110111 |
3 | 1100221111102121220 |
4 | 133212031220313 |
5 | 2041202023111 |
6 | 124334041423 |
7 | 16064604132 |
oct | 3746155067 |
9 | 1327442556 |
10 | 530111031 |
11 | 25226329a |
12 | 129649273 |
13 | 85a98788 |
14 | 50593219 |
15 | 31814e06 |
hex | 1f98da37 |
530111031 has 4 divisors (see below), whose sum is σ = 706814712. Its totient is φ = 353407352.
The previous prime is 530111011. The next prime is 530111033. The reversal of 530111031 is 130111035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 530111031 - 211 = 530108983 is a prime.
It is a super-2 number, since 2×5301110312 = 562035410375765922, which contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 530111031.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530111033) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88351836 + ... + 88351841.
It is an arithmetic number, because the mean of its divisors is an integer number (176703678).
Almost surely, 2530111031 is an apocalyptic number.
530111031 is a deficient number, since it is larger than the sum of its proper divisors (176703681).
530111031 is a wasteful number, since it uses less digits than its factorization.
530111031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 176703680.
The product of its (nonzero) digits is 45, while the sum is 15.
The square root of 530111031 is about 23024.1401793856. The cubic root of 530111031 is about 809.3237413034.
Adding to 530111031 its reverse (130111035), we get a palindrome (660222066).
The spelling of 530111031 in words is "five hundred thirty million, one hundred eleven thousand, thirty-one".
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