Base | Representation |
---|---|
bin | 11000000110110100111011… |
… | …01101111011110000101001 |
3 | 20221200210222222001122120002 |
4 | 30003122131231323300221 |
5 | 23422013244400301101 |
6 | 304424551131312345 |
7 | 14110633164656354 |
oct | 1403323555736051 |
9 | 227623888048502 |
10 | 53011132431401 |
11 | 159889932952a1 |
12 | 5b41ab4bab6b5 |
13 | 2376c0b7378a1 |
14 | d13a76c0529b |
15 | 61de1b8a1d6b |
hex | 30369db7bc29 |
53011132431401 has 8 divisors (see below), whose sum is σ = 53658140407200. Its totient is φ = 52364322542272.
The previous prime is 53011132431379. The next prime is 53011132431449. The reversal of 53011132431401 is 10413423111035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53011132431401 - 222 = 53011128237097 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53011132431451) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 48983135 + ... + 50053668.
It is an arithmetic number, because the mean of its divisors is an integer number (6707267550900).
Almost surely, 253011132431401 is an apocalyptic number.
It is an amenable number.
53011132431401 is a deficient number, since it is larger than the sum of its proper divisors (647007975799).
53011132431401 is an equidigital number, since it uses as much as digits as its factorization.
53011132431401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 99043335.
The product of its (nonzero) digits is 4320, while the sum is 29.
Adding to 53011132431401 its reverse (10413423111035), we get a palindrome (63424555542436).
The spelling of 53011132431401 in words is "fifty-three trillion, eleven billion, one hundred thirty-two million, four hundred thirty-one thousand, four hundred one".
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