5301123114041 has 4 divisors (see below), whose sum is σ = 5355773867892. Its totient is φ = 5246472360192.

The previous prime is 5301123114031. The next prime is 5301123114101. The reversal of 5301123114041 is 1404113211035.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4054262790400 + 1246860323641 = 2013520^2 + 1116629^2 .

It is a cyclic number.

It is not a de Polignac number, because 5301123114041 - 2¹⁰ = 5301123113017 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 5301123114041.

It is not an unprimeable number, because it can be changed into a prime (5301123114031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27325376780 + ... + 27325376973.

It is an arithmetic number, because the mean of its divisors is an integer number (1338943466973).

Almost surely, 2^{5301123114041} is an apocalyptic number.

It is an amenable number.

5301123114041 is a deficient number, since it is larger than the sum of its proper divisors (54650753851).

5301123114041 is an equidigital number, since it uses as much as digits as its factorization.

5301123114041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 54650753850.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 5301123114041 its reverse (1404113211035), we get a palindrome (6705236325076).

The spelling of 5301123114041 in words is "five trillion, three hundred one billion, one hundred twenty-three million, one hundred fourteen thousand, forty-one".