53011331 has 4 divisors (see below), whose sum is σ = 53506872. Its totient is φ = 52515792.

The previous prime is 53011327. The next prime is 53011339. The reversal of 53011331 is 13311035.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13311035 = 5 ⋅2662207.

It is a cyclic number.

It is not a de Polignac number, because 53011331 - 2² = 53011327 is a prime.

It is a super-3 number, since 3×53011331³ (a number of 24 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53011339) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 247610 + ... + 247823.

It is an arithmetic number, because the mean of its divisors is an integer number (13376718).

Almost surely, 2^53011331 is an apocalyptic number.

53011331 is a deficient number, since it is larger than the sum of its proper divisors (495541).

53011331 is a wasteful number, since it uses less digits than its factorization.

53011331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 495540.

The product of its (nonzero) digits is 135, while the sum is 17.

The square root of 53011331 is about 7280.8880639658. Note that the first 3 decimals coincide. The cubic root of 53011331 is about 375.6553423662.

Adding to 53011331 its reverse (13311035), we get a palindrome (66322366).

The spelling of 53011331 in words is "fifty-three million, eleven thousand, three hundred thirty-one".