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495433 is a prime number
BaseRepresentation
bin1111000111101001001
3221011121101
41320331021
5111323213
614341401
74132261
oct1707511
9834541
10495433
11309254
121ba861
13144673
14cc7a1
159bbdd
hex78f49

495433 has 2 divisors, whose sum is σ = 495434. Its totient is φ = 495432.

The previous prime is 495421. The next prime is 495437. The reversal of 495433 is 334594.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 262144 + 233289 = 512^2 + 483^2 .

It is a cyclic number.

It is not a de Polignac number, because 495433 - 25 = 495401 is a prime.

It is a plaindrome in base 15.

It is not a weakly prime, because it can be changed into another prime (495437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 247716 + 247717.

It is an arithmetic number, because the mean of its divisors is an integer number (247717).

2495433 is an apocalyptic number.

It is an amenable number.

495433 is a deficient number, since it is larger than the sum of its proper divisors (1).

495433 is an equidigital number, since it uses as much as digits as its factorization.

495433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6480, while the sum is 28.

The square root of 495433 is about 703.8700164093. The cubic root of 495433 is about 79.1276577285.

The spelling of 495433 in words is "four hundred ninety-five thousand, four hundred thirty-three".