Base | Representation |
---|---|
bin | 100110100100100010010… |
… | …1010011101001101100011 |
3 | 200202210011200012122101202 |
4 | 1031021010222131031203 |
5 | 1143323214223424101 |
6 | 15135151050351415 |
7 | 1054665142220366 |
oct | 115110452351543 |
9 | 20683150178352 |
10 | 5301141623651 |
11 | 1764224278585 |
12 | 71749172b56b |
13 | 2c5b84588413 |
14 | 1448103800dd |
15 | 92d6523936b |
hex | 4d244a9d363 |
5301141623651 has 4 divisors (see below), whose sum is σ = 5301887955072. Its totient is φ = 5300395292232.
The previous prime is 5301141623641. The next prime is 5301141623677. The reversal of 5301141623651 is 1563261411035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5301141623651 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5301141623641) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 373155056 + ... + 373169261.
It is an arithmetic number, because the mean of its divisors is an integer number (1325471988768).
Almost surely, 25301141623651 is an apocalyptic number.
5301141623651 is a deficient number, since it is larger than the sum of its proper divisors (746331421).
5301141623651 is an equidigital number, since it uses as much as digits as its factorization.
5301141623651 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 746331420.
The product of its (nonzero) digits is 64800, while the sum is 38.
The spelling of 5301141623651 in words is "five trillion, three hundred one billion, one hundred forty-one million, six hundred twenty-three thousand, six hundred fifty-one".
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