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53011534113 = 325890170457
BaseRepresentation
bin110001010111101110…
…111101000100100001
312001211110112221210100
4301113232331010201
51332031423042423
640204141053013
73554450414406
oct612756750441
9161743487710
1053011534113
11205336a121a
12a335557169
134cca962185
1427cc69a2ad
1515a3e66343
hexc57bbd121

53011534113 has 6 divisors (see below), whose sum is σ = 76572215954. Its totient is φ = 35341022736.

The previous prime is 53011534087. The next prime is 53011534133. The reversal of 53011534113 is 31143511035.

It is a happy number.

53011534113 is a `hidden beast` number, since 5 + 3 + 0 + 11 + 534 + 113 = 666.

It can be written as a sum of positive squares in only one way, i.e., 29327247504 + 23684286609 = 171252^2 + 153897^2 .

It is not a de Polignac number, because 53011534113 - 217 = 53011403041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53011534133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 2945085220 + ... + 2945085237.

Almost surely, 253011534113 is an apocalyptic number.

It is an amenable number.

53011534113 is a deficient number, since it is larger than the sum of its proper divisors (23560681841).

53011534113 is a wasteful number, since it uses less digits than its factorization.

53011534113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5890170463 (or 5890170460 counting only the distinct ones).

The product of its (nonzero) digits is 2700, while the sum is 27.

The spelling of 53011534113 in words is "fifty-three billion, eleven million, five hundred thirty-four thousand, one hundred thirteen".

Divisors: 1 3 9 5890170457 17670511371 53011534113