Base | Representation |
---|---|
bin | 100110100100100110000… |
… | …1000010101111100111001 |
3 | 200202210111101221021112001 |
4 | 1031021030020111330321 |
5 | 1143323443311224440 |
6 | 15135211323421001 |
7 | 1055001223102036 |
oct | 115111410257471 |
9 | 20683441837461 |
10 | 5301266898745 |
11 | 1764288a62614 |
12 | 717507684761 |
13 | 2c5ba450b3ac |
14 | 144822c7038d |
15 | 92d71232b9a |
hex | 4d24c215f39 |
5301266898745 has 16 divisors (see below), whose sum is σ = 6509575258560. Its totient is φ = 4142313612864.
The previous prime is 5301266898731. The next prime is 5301266898761. The reversal of 5301266898745 is 5478986621035.
It is a cyclic number.
It is not a de Polignac number, because 5301266898745 - 211 = 5301266896697 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14638266 + ... + 14996044.
It is an arithmetic number, because the mean of its divisors is an integer number (406848453660).
It is a 1-persistent number, because it is pandigital, but 2⋅5301266898745 = 10602533797490 is not.
Almost surely, 25301266898745 is an apocalyptic number.
It is an amenable number.
5301266898745 is a deficient number, since it is larger than the sum of its proper divisors (1208308359815).
5301266898745 is a wasteful number, since it uses less digits than its factorization.
5301266898745 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 426744.
The product of its (nonzero) digits is 87091200, while the sum is 64.
The spelling of 5301266898745 in words is "five trillion, three hundred one billion, two hundred sixty-six million, eight hundred ninety-eight thousand, seven hundred forty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •