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5301331243 = 13407794711
BaseRepresentation
bin1001110111111101…
…11110010100101011
3111200110101112022121
410323332332110223
541324120044433
62234013532111
7245241400135
oct47376762453
914613345277
105301331243
11228051069a
12103b4a4037
136664045c0
14384100055
15210629c2d
hex13bfbe52b

5301331243 has 4 divisors (see below), whose sum is σ = 5709125968. Its totient is φ = 4893536520.

The previous prime is 5301331241. The next prime is 5301331247. The reversal of 5301331243 is 3421331035.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5301331243 - 21 = 5301331241 is a prime.

It is a super-2 number, since 2×53013312432 = 56208225896015850098, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (5301331241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 203897343 + ... + 203897368.

It is an arithmetic number, because the mean of its divisors is an integer number (1427281492).

Almost surely, 25301331243 is an apocalyptic number.

5301331243 is a deficient number, since it is larger than the sum of its proper divisors (407794725).

5301331243 is a wasteful number, since it uses less digits than its factorization.

5301331243 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 407794724.

The product of its (nonzero) digits is 3240, while the sum is 25.

The square root of 5301331243 is about 72810.2413332081. The cubic root of 5301331243 is about 1743.6593664039.

Adding to 5301331243 its reverse (3421331035), we get a palindrome (8722662278).

The spelling of 5301331243 in words is "five billion, three hundred one million, three hundred thirty-one thousand, two hundred forty-three".

Divisors: 1 13 407794711 5301331243