53013454042 has 4 divisors (see below), whose sum is σ = 79520181066. Its totient is φ = 26506727020.

The previous prime is 53013454019. The next prime is 53013454073. The reversal of 53013454042 is 24045431035.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 31474662921 + 21538791121 = 177411^2 + 146761^2 .

It is a super-2 number, since 2×53013454042² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 53013453995 and 53013454013.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13253363509 + ... + 13253363512.

Almost surely, 2^53013454042 is an apocalyptic number.

53013454042 is a deficient number, since it is larger than the sum of its proper divisors (26506727024).

53013454042 is a wasteful number, since it uses less digits than its factorization.

53013454042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26506727023.

The product of its (nonzero) digits is 28800, while the sum is 31.

Adding to 53013454042 its reverse (24045431035), we get a palindrome (77058885077).

The spelling of 53013454042 in words is "fifty-three billion, thirteen million, four hundred fifty-four thousand, forty-two".