5301420241035 has 8 divisors (see below), whose sum is σ = 8482272385680. Its totient is φ = 2827424128544.

The previous prime is 5301420241009. The next prime is 5301420241057.

5301420241035 is nontrivially palindromic in base 10.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5301420241035 - 2⁵ = 5301420241003 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5301420240993 and 5301420241011.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 176714008020 + ... + 176714008049.

It is an arithmetic number, because the mean of its divisors is an integer number (1060284048210).

Almost surely, 2^{5301420241035} is an apocalyptic number.

5301420241035 is a deficient number, since it is larger than the sum of its proper divisors (3180852144645).

5301420241035 is a wasteful number, since it uses less digits than its factorization.

5301420241035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 353428016077.

The product of its (nonzero) digits is 14400, while the sum is 30.

It can be divided in two parts, 5301420 and 241035, that added together give a palindrome (5542455).

The spelling of 5301420241035 in words is "five trillion, three hundred one billion, four hundred twenty million, two hundred forty-one thousand, thirty-five".