Base | Representation |
---|---|
bin | 11000000110111010101100… |
… | …10111100100001100000101 |
3 | 20221201002222212100100120221 |
4 | 30003131112113210030011 |
5 | 23422041120432241040 |
6 | 304430222354424341 |
7 | 14111103022605622 |
oct | 1403352627441405 |
9 | 227632885310527 |
10 | 53014230352645 |
11 | 1598a232a57391 |
12 | 5b4261a5920b1 |
13 | 23772b34b5693 |
14 | d13c8c41b349 |
15 | 61e04d83974a |
hex | 3037565e4305 |
53014230352645 has 4 divisors (see below), whose sum is σ = 63617076423180. Its totient is φ = 42411384282112.
The previous prime is 53014230352621. The next prime is 53014230352747. The reversal of 53014230352645 is 54625303241035.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 29628088762561 + 23386141590084 = 5443169^2 + 4835922^2 .
It is a cyclic number.
It is not a de Polignac number, because 53014230352645 - 241 = 50815207097093 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5301423035260 + ... + 5301423035269.
It is an arithmetic number, because the mean of its divisors is an integer number (15904269105795).
Almost surely, 253014230352645 is an apocalyptic number.
It is an amenable number.
53014230352645 is a deficient number, since it is larger than the sum of its proper divisors (10602846070535).
53014230352645 is a wasteful number, since it uses less digits than its factorization.
53014230352645 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10602846070534.
The product of its (nonzero) digits is 1296000, while the sum is 43.
The spelling of 53014230352645 in words is "fifty-three trillion, fourteen billion, two hundred thirty million, three hundred fifty-two thousand, six hundred forty-five".
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