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53014231151 = 77573461593
BaseRepresentation
bin110001010111111001…
…001111100001101111
312001211122121222102122
4301113321033201233
51332033120344101
640204314543155
73554512346450
oct612771174157
9161748558378
1053014231151
1120535173582
12a336437abb
134ccb39795b
1427ccb9d127
1515a42ea51b
hexc57e4f86f

53014231151 has 4 divisors (see below), whose sum is σ = 60587692752. Its totient is φ = 45440769552.

The previous prime is 53014231147. The next prime is 53014231181. The reversal of 53014231151 is 15113241035.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53014231151 - 22 = 53014231147 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 53014231151.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53014231121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3786730790 + ... + 3786730803.

It is an arithmetic number, because the mean of its divisors is an integer number (15146923188).

Almost surely, 253014231151 is an apocalyptic number.

53014231151 is a deficient number, since it is larger than the sum of its proper divisors (7573461601).

53014231151 is an equidigital number, since it uses as much as digits as its factorization.

53014231151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7573461600.

The product of its (nonzero) digits is 1800, while the sum is 26.

Adding to 53014231151 its reverse (15113241035), we get a palindrome (68127472186).

The spelling of 53014231151 in words is "fifty-three billion, fourteen million, two hundred thirty-one thousand, one hundred fifty-one".

Divisors: 1 7 7573461593 53014231151