Base | Representation |
---|---|
bin | 110001010111111001… |
… | …010100101000001101 |
3 | 12001211122200001002111 |
4 | 301113321110220031 |
5 | 1332033122031140 |
6 | 40204315224021 |
7 | 3554512464406 |
oct | 612771245015 |
9 | 161748601074 |
10 | 53014252045 |
11 | 20535188247 |
12 | a336448011 |
13 | 4ccb3a4311 |
14 | 27ccba69ad |
15 | 15a43017ea |
hex | c57e54a0d |
53014252045 has 4 divisors (see below), whose sum is σ = 63617102460. Its totient is φ = 42411401632.
The previous prime is 53014252043. The next prime is 53014252061. The reversal of 53014252045 is 54025241035.
53014252045 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 6567967849 + 46446284196 = 81043^2 + 215514^2 .
It is a cyclic number.
It is not a de Polignac number, because 53014252045 - 21 = 53014252043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53014251998 and 53014252016.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53014252043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5301425200 + ... + 5301425209.
It is an arithmetic number, because the mean of its divisors is an integer number (15904275615).
Almost surely, 253014252045 is an apocalyptic number.
It is an amenable number.
53014252045 is a deficient number, since it is larger than the sum of its proper divisors (10602850415).
53014252045 is a wasteful number, since it uses less digits than its factorization.
53014252045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10602850414.
The product of its (nonzero) digits is 24000, while the sum is 31.
The spelling of 53014252045 in words is "fifty-three billion, fourteen million, two hundred fifty-two thousand, forty-five".
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