Base | Representation |
---|---|
bin | 110001010111111001… |
… | …111101111011110001 |
3 | 12001211122222122011201 |
4 | 301113321331323301 |
5 | 1332033142434413 |
6 | 40204323011201 |
7 | 3554514100564 |
oct | 612771757361 |
9 | 161748878151 |
10 | 53014421233 |
11 | 20535293374 |
12 | a336509b01 |
13 | 4ccb433327 |
14 | 27ccc0c4db |
15 | 15a43369dd |
hex | c57e7def1 |
53014421233 has 8 divisors (see below), whose sum is σ = 53514834560. Its totient is φ = 52514263440.
The previous prime is 53014421221. The next prime is 53014421263. The reversal of 53014421233 is 33212441035.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53014421233 - 213 = 53014413041 is a prime.
It is a super-2 number, since 2×530144212332 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53014421263) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 366616 + ... + 490342.
It is an arithmetic number, because the mean of its divisors is an integer number (6689354320).
Almost surely, 253014421233 is an apocalyptic number.
It is an amenable number.
53014421233 is a deficient number, since it is larger than the sum of its proper divisors (500413327).
53014421233 is a wasteful number, since it uses less digits than its factorization.
53014421233 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 127767.
The product of its (nonzero) digits is 8640, while the sum is 28.
Adding to 53014421233 its reverse (33212441035), we get a palindrome (86226862268).
The spelling of 53014421233 in words is "fifty-three billion, fourteen million, four hundred twenty-one thousand, two hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •