Base | Representation |
---|---|
bin | 11000000110111011010000… |
… | …11100001000110010101011 |
3 | 20221201010202222211220212120 |
4 | 30003131220130020302223 |
5 | 23422042231041303120 |
6 | 304430312425042323 |
7 | 14111113363635033 |
oct | 1403355034106253 |
9 | 227633688756776 |
10 | 53014533541035 |
11 | 1598a379109300 |
12 | 5b426a40263a3 |
13 | 237733125b7b1 |
14 | d13cba7c08c3 |
15 | 61e06a278140 |
hex | 303768708cab |
53014533541035 has 24 divisors (see below), whose sum is σ = 93235477172880. Its totient is φ = 25704016261440.
The previous prime is 53014533541019. The next prime is 53014533541049.
53014533541035 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 53014533541035 - 24 = 53014533541019 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 14604552880 + ... + 14604556509.
It is an arithmetic number, because the mean of its divisors is an integer number (3884811548870).
Almost surely, 253014533541035 is an apocalyptic number.
53014533541035 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53014533541035 is a deficient number, since it is larger than the sum of its proper divisors (40220943631845).
53014533541035 is a wasteful number, since it uses less digits than its factorization.
53014533541035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 29209109419 (or 29209109408 counting only the distinct ones).
The product of its (nonzero) digits is 810000, while the sum is 42.
It can be divided in two parts, 5301453 and 3541035, that added together give a palindrome (8842488).
The spelling of 53014533541035 in words is "fifty-three trillion, fourteen billion, five hundred thirty-three million, five hundred forty-one thousand, thirty-five".
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