53015014000001 has 4 divisors (see below), whose sum is σ = 53202346205232. Its totient is φ = 52827681794772.

The previous prime is 53015013999929. The next prime is 53015014000009. The reversal of 53015014000001 is 10000041051035.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-53015014000001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53015014000009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93666102191 + ... + 93666102756.

It is an arithmetic number, because the mean of its divisors is an integer number (13300586551308).

Almost surely, 2^{53015014000001} is an apocalyptic number.

It is an amenable number.

53015014000001 is a deficient number, since it is larger than the sum of its proper divisors (187332205231).

53015014000001 is a wasteful number, since it uses less digits than its factorization.

53015014000001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 187332205230.

The product of its (nonzero) digits is 300, while the sum is 20.

Adding to 53015014000001 its reverse (10000041051035), we get a palindrome (63015055051036).

The spelling of 53015014000001 in words is "fifty-three trillion, fifteen billion, fourteen million, one", and thus it is an aban number.