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53015014000000 = 2756132637753
BaseRepresentation
bin11000000110111100001010…
…00100111100010110000000
320221201012000110220202200001
430003132011010330112000
523422044222041000000
6304430432231005344
714111131316524033
oct1403360504742600
9227635013822601
1053015014000000
111598a5a5339228
125b427b8b09854
1323773a9961340
14d13d2452b01a
1561e09753146a
hex30378513c580

53015014000000 has 448 divisors, whose sum is σ = 142732351127520. Its totient is φ = 19497830400000.

The previous prime is 53015013999929. The next prime is 53015014000009. The reversal of 53015014000000 is 41051035.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53015014000009) by changing a digit.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 6837996124 + ... + 6838003876.

Almost surely, 253015014000000 is an apocalyptic number.

53015014000000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 53015014000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (71366175563760).

53015014000000 is an abundant number, since it is smaller than the sum of its proper divisors (89717337127520).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

53015014000000 is an frugal number, since it uses more digits than its factorization.

53015014000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8073 (or 8036 counting only the distinct ones).

The product of its (nonzero) digits is 300, while the sum is 19.

Adding to 53015014000000 its reverse (41051035), we get a palindrome (53015055051035).

The spelling of 53015014000000 in words is "fifty-three trillion, fifteen billion, fourteen million", and thus it is an aban number.