Base | Representation |
---|---|
bin | 110001010111111100… |
… | …010010110101110001 |
3 | 12001211201010121211100 |
4 | 301113330102311301 |
5 | 1332033321444103 |
6 | 40204344035013 |
7 | 3554522221020 |
oct | 612774226561 |
9 | 161751117740 |
10 | 53015031153 |
11 | 2053566a637 |
12 | a336762a69 |
13 | 4ccb5b7b26 |
14 | 27ccd2a8b7 |
15 | 15a44075a3 |
hex | c57f12d71 |
53015031153 has 24 divisors (see below), whose sum is σ = 87615635328. Its totient is φ = 30260117952.
The previous prime is 53015031151. The next prime is 53015031163. The reversal of 53015031153 is 35113051035.
53015031153 is a `hidden beast` number, since 5 + 3 + 0 + 1 + 503 + 1 + 153 = 666.
It is not a de Polignac number, because 53015031153 - 21 = 53015031151 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53015031151) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 418476 + ... + 530237.
It is an arithmetic number, because the mean of its divisors is an integer number (3650651472).
Almost surely, 253015031153 is an apocalyptic number.
It is an amenable number.
53015031153 is a deficient number, since it is larger than the sum of its proper divisors (34600604175).
53015031153 is a wasteful number, since it uses less digits than its factorization.
53015031153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 949613 (or 949610 counting only the distinct ones).
The product of its (nonzero) digits is 3375, while the sum is 27.
Adding to 53015031153 its reverse (35113051035), we get a palindrome (88128082188).
The spelling of 53015031153 in words is "fifty-three billion, fifteen million, thirty-one thousand, one hundred fifty-three".
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