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530154335 = 5106030867
BaseRepresentation
bin11111100110011…
…000001101011111
31100221120122000202
4133212120031133
52041204414320
6124335014115
716065144314
oct3746301537
91327518022
10530154335
11252292887
1212966a33b
1385ab23b9
14505a4d0b
1531822b75
hex1f99835f

530154335 has 4 divisors (see below), whose sum is σ = 636185208. Its totient is φ = 424123464.

The previous prime is 530154323. The next prime is 530154337. The reversal of 530154335 is 533451035.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 530154335 - 210 = 530153311 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 530154298 and 530154307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (530154337) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53015429 + ... + 53015438.

It is an arithmetic number, because the mean of its divisors is an integer number (159046302).

Almost surely, 2530154335 is an apocalyptic number.

530154335 is a deficient number, since it is larger than the sum of its proper divisors (106030873).

530154335 is a wasteful number, since it uses less digits than its factorization.

530154335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 106030872.

The product of its (nonzero) digits is 13500, while the sum is 29.

The square root of 530154335 is about 23025.0805644627. The cubic root of 530154335 is about 809.3457781969.

The spelling of 530154335 in words is "five hundred thirty million, one hundred fifty-four thousand, three hundred thirty-five".

Divisors: 1 5 106030867 530154335