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530211404551 = 677913603053
BaseRepresentation
bin1111011011100110000…
…11111111101100000111
31212200120100022002010211
413231303003333230013
532141333104421201
61043324210300251
753210063402113
oct7556303775407
91780510262124
10530211404551
11194952573934
1286912887687
133acca26110a
141b93b77c743
15dbd30ba651
hex7b730ffb07

530211404551 has 4 divisors (see below), whose sum is σ = 538125007672. Its totient is φ = 522297801432.

The previous prime is 530211404507. The next prime is 530211404561. The reversal of 530211404551 is 155404112035.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 530211404551 - 235 = 495851666183 is a prime.

It is a super-2 number, since 2×5302114045512 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (530211404561) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3956801460 + ... + 3956801593.

It is an arithmetic number, because the mean of its divisors is an integer number (134531251918).

Almost surely, 2530211404551 is an apocalyptic number.

530211404551 is a deficient number, since it is larger than the sum of its proper divisors (7913603121).

530211404551 is an equidigital number, since it uses as much as digits as its factorization.

530211404551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7913603120.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 530211404551 its reverse (155404112035), we get a palindrome (685615516586).

The spelling of 530211404551 in words is "five hundred thirty billion, two hundred eleven million, four hundred four thousand, five hundred fifty-one".

Divisors: 1 67 7913603053 530211404551